0=(7x^2+18x+40)

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Solution for 0=(7x^2+18x+40) equation: 



0=(7x^2+18x+40)

We move all terms to the left:

0-((7x^2+18x+40))=0

We add all the numbers together, and all the variables

-((7x^2+18x+40))=0



We calculate terms in parentheses: -((7x^2+18x+40)), so:

(7x^2+18x+40)

We get rid of parentheses

7x^2+18x+40

Back to the equation:

-(7x^2+18x+40)



We get rid of parentheses

-7x^2-18x-40=0

a = -7; b = -18; c = -40;
Δ = b2-4ac
Δ = -182-4·(-7)·(-40)
Δ = -796
Delta is less than zero, so there is no solution for the equation

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